3.6_teamteach_ipynb_2_

• 3 min read 

# Step 1: Add a variable that represents temperature
temperature = 50  # You can change this value to test different conditions

if 65 <= temperature <= 80:
    print("It's a comfortable day")
# Step 2: Check if it’s a hot day
else: 
    print("I don't like this weather.")

I don't like this weather.

Popcorn Hack #1

  • Conditions in JavaScript
  • How would you change the code to show a message for scores below 60? What would you add?
%%js

let score = 50;
if (50 >= 60) {
    console.log("You passed!");
} else {
    console.log("Maybe study!");
}


<IPython.core.display.Javascript object>

Python HW Hack #1

# Define the function check_odd_even
def check_odd_even(number):
    # Check if the number is divisible by 2
    if number % 2 == 0:
        return "Even"
    else:
        return "Odd"

# Test the function with different numbers
print(check_odd_even(10))  # Output: Even
print(check_odd_even(7))   # Output: Odd
print(check_odd_even(0))   # Output: Even
print(check_odd_even(33))  # Output: Odd


Even
Odd
Even
Odd

Python HW Hack #2

# Define the function is_leap_year
def is_leap_year(year):
    # Check if the year is divisible by 4 but not 100, or divisible by 400
    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
        return "Leap Year"
    else:
        return "Not a Leap Year"

# Test the function with different years
print(is_leap_year(2020))  # Output: Leap Year
print(is_leap_year(1900))  # Output: Not a Leap Year
print(is_leap_year(2000))  # Output: Leap Year
print(is_leap_year(2023))  # Output: Not a Leap Year


Leap Year
Not a Leap Year
Leap Year
Not a Leap Year

Python HW Hack #3

# Define the function temperature_range
def temperature_range(temperature):
    # Use if...elif...else statements to categorize the temperature
    if temperature < 60:
        return "Cold"
    elif 60 <= temperature <= 80:
        return "Warm"
    elif temperature > 85:
        return "Hot"
    else:
        return "Undefined Range"  # For temperatures between 81°F and 85°F

# Test the function with different temperature values
print(temperature_range(55))  # Output: Cold
print(temperature_range(75))  # Output: Warm
print(temperature_range(90))  # Output: Hot
print(temperature_range(83))  # Output: Undefined Range

JavaScript HW Hack #1

%%js
public class VotingEligibility {
    // Define the function checkVotingEligibility
    public static String checkVotingEligibility(int age) {
        // Check if the age is 18 or older
        if (age >= 18) {
            return "You are eligible to vote!";
        } else {
            return "You are not eligible to vote yet.";
        }
    }

    public static void main(String[] args) {
        // Test the function with different age values
        System.out.println(checkVotingEligibility(20));  // Output: You are eligible to vote!
        System.out.println(checkVotingEligibility(16));  // Output: You are not eligible to vote yet.
        System.out.println(checkVotingEligibility(18));  // Output: You are eligible to vote!
    }
}


<IPython.core.display.Javascript object>

JavaScript HW Hack #2

%%js
public class GradeCalculator {
    // Define the function getGrade
    public static String getGrade(int score) {
        // Use if...else if...else statements to determine the letter grade
        if (score >= 90) {
            return "Grade: A";
        } else if (score >= 80) {
            return "Grade: B";
        } else if (score >= 70) {
            return "Grade: C";
        } else {
            return "Grade: F";
        }
    }

    public static void main(String[] args) {
        // Test the function with different scores
        System.out.println(getGrade(95));  // Output: Grade: A
        System.out.println(getGrade(85));  // Output: Grade: B
        System.out.println(getGrade(75));  // Output: Grade: C
        System.out.println(getGrade(65));  // Output: Grade: F
    }
}


<IPython.core.display.Javascript object>

JavaScript HW Hack #3

%%js

public class TemperatureConverter {
    // Define the function convertTemperature
    public static String convertTemperature(double value, String scale) {
        // Check if the scale is "C" or "F"
        if (scale.equalsIgnoreCase("C")) {
            // Convert Celsius to Fahrenheit
            double fahrenheit = (value * 9/5) + 32;
            return String.format("%.2f°C is %.2f°F", value, fahrenheit);
        } else if (scale.equalsIgnoreCase("F")) {
            // Convert Fahrenheit to Celsius
            double celsius = (value - 32) * 5/9;
            return String.format("%.2f°F is %.2f°C", value, celsius);
        } else {
            // If scale is neither "C" nor "F", return an error message
            return "Error: Invalid scale. Please use 'C' for Celsius or 'F' for Fahrenheit.";
        }
    }

    public static void main(String[] args) {
        // Test the function with different values and scales
        System.out.println(convertTemperature(25, "C"));  // Output: 25.00°C is 77.00°F
        System.out.println(convertTemperature(77, "F"));  // Output: 77.00°F is 25.00°C
        System.out.println(convertTemperature(100, "X")); // Output: Error: Invalid scale. Please use 'C' or 'F'.
    }
}


<IPython.core.display.Javascript object>